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(C) In the reaction $NH_3 + BF_3 	o NH_3.BF_3$,$NH_3$ acts as a Lewis base and $BF_3$ acts as a Lewis acid.$1$. In $NH_3$,the $N$ atom is $sp^3$ hybr

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Bond angle around $B$ increases

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(C) In the reaction $NH_3 + BF_3 	o NH_3.BF_3$,$NH_3$ acts as a Lewis base and $BF_3$ acts as a Lewis acid.$1$. In $NH_3$,the $N$ atom is $sp^3$ hybridized with a lone pair. Upon formation of the adduct,the lone pair is donated to $B$,causing the $H-N-H$ bond angle to decrease due to the change in hybridization and steric factors.$2$. In $BF_3$,the $B$ atom is $sp^2$ hybridized (trigonal planar,$120^\circ$). In the adduct $NH_3.BF_3$,the $B$ atom becomes $sp^3$ hybridized (tetrahedral,$\approx 109.5^\circ$). Thus,the bond angle around $B$ decreases,not increases.$3$. As $B$ changes from $sp^2$ to $sp^3$,the $s$-character in its hybrid orbitals decreases (from $33.3\%$ to $25\%$).$4$. The $B-F$ bond length increases because the hybridization changes from $sp^2$ to $sp^3$,reducing the double bond character present in $BF_3$ due to back-bonding.

Which one of the following is not correct for the reaction given below:
$NH_3 + BF_3 \to NH_3.BF_3$

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Which one of the following is not correct for the reaction given below:$NH_3 + BF_3 \to NH_3.BF_3$